Sort a array, [W B W B B W W B ] === [W W W W B B B B ]

Question

Anonymous · Accepted Answer

I failed, but finally I got the answer:
void sort(String[] arr){
		  int start = 0;
		  int end = arr.length -1;
		  while(start < end){
			  while(arr[start].equals("W")){
				  start++;
			  }
			  while(arr[end].equals("B")){
				  end--;
			  }
			  if(start < end){
				  arr[start] = "W";
				  arr[end] = "B";
			  }
			  start++;
			  end--;
		  }
		  
	}

Very Simple Solution · Answer

import java.util.*;
public class SortCharArray {
public static void main(String[] args) { 

int o = 1;
int t = 2;
char[] a = {'W','W','B','W','B','B','W','B'};
System.out.println("Unsorted Array: "+Arrays.toString(a));
for(int i=0;i

Anonymous · Answer

String string = new WBArray().takeStringInput();
        char[] chars = string.toCharArray();
        int start =0;
        int end = chars.length-1;

        char[] newCharArr = new char[chars.length];

        for(int i=0;i

Anonymous · Answer

private String[] sort(String[] list){
  ArrayList list = new ArrayList();
  for(i in list) {
     if (i.equals("W"){
        list.add(0,i)
      } else{
      list.add("B")
     }
  }
 return list.toArray()
}
}

Solution · Answer

String string = new WBArray().takeStringInput();
        char[] chars = string.toCharArray();
        int start =0;
        int end = chars.length-1;

        char[] newCharArr = new char[chars.length];
        
        for(int i=0;i

Anonymous · Answer

int main() {
string str("BBWBBWBWBBW");
int f=0;
for(int j=1; j < str.length(); j++){
    if(str[j-1]=='B' && str[j]=='W')
        swap(str[f++], str[j]);
    else if(str[j-1]=='W')
        f++;
}
    cout<

Anonymous · Answer

for(int i=0;i

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